Theorem

Let A be an object. Let X and Y be members of ℘(A). Let a be a member of A. Assume ¬aXY. Then we have ¬aY.

Background

The following background is necessary to understand this theorem.

(.) Let A and x be objects. Then xA is a proposition.

(.) Let φ be a proposition. Then ¬φ is a proposition.

(.) Let A be an object. Then ℘(A) is an object.

(.) Let A and B be objects. Then "AB" is an object.

Background for Proof

The following background is necessary for the proof.

(.) Let φ and ψ be propositions. Assume φ implies ψ and ¬ψ. Then we know ¬φ.

(.) Let A, B and x be objects. Assume xB. Then we know xAB.

Proof

We have aY implies aXY. Using this and ¬aXY, we conclude ¬aY.


Click here to modify variable names (JavaScript Must Be Enabled).

Hide Background.

Test yourself on this item.


See Also

Theorem Theorem Theorem


Feedback